Invalid Label Error When Eval JSON

Written by on Oct 25 2007

If you are getting an “invalid label” error when doing eval() on a json string, here is the solution:

You must do eval(‘(’ + jsonObj + ‘)’) to fix this. I know this seems really stupid, but shows just this same example. I wrote a function to handle this:

function jeval(str){return eval(‘(’ + str + ‘)’)}

and then I call jeval() instead of eval();


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