"invalid label" Error When Eval JSON

If you are getting an "invalid label" error when doing eval() on a json string, here is the solution:

You must do eval('(' + jsonObj + ')') to fix this. I know this seems really stupid, but http://www.json.org/js.html shows just this same example. I wrote a function to handle this:

function jeval(str){return eval('(' +  str + ')')}

and then I call jeval() instead of eval();

2 Comments

goutham said on June 12, 2012

Thank You,its working.but may i know the reason please.

Steven Bristol said on June 12, 2012

It’s because the parenthesis are required for javascript to know what to do with it.